a

A=(a*4)-(1*2)

Zeige alle Werte in der Tabelle die a annehmen kann 
und berechen dazu den Flächeninhalt 
mit deinen unterschiedlichen Werten

Lass dir die Lösung deines Termes immer 
in Abhängigkeit von a anzeigen

Lass dir zum Vergleich den Flächeninhalt 
von GeoGebra berechnen

Tipp 1

Tipp 2

Tipp 3

Tipp 4

A

(a*4)-(1*2)

(a*2)+((a-1)*2)

(a-1)*4+(1*2)

a=

dynamischer

Flächeninhalt

a=

Flächeninhalt

von Geogebra

a

ABCDEG

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.

.

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Supertipp

Schau in der Tabelle ab Spalte N

a = 10 (slider from 1 to 10, step 1)
A = Point(yAxis)
B = Point(xAxis)
C = (2, 1)
D = (4, 1)
G = Point(Circle[A, a])
h = Segment(A, G)
E = Point(Circle[D, a - 1])
b = Segment(D, E)
Vieleck1, g, a_1, b_1, c, d, e = Polygon(G, A, B, C, D, E)
F = Midpoint(G, A)
TextVieleck1: "Fläche von  " + (Name[G]) + (Name[A]) + (Name[B]) + (Name[C]) + (Name[D]) + (Name[E]) + " = " + Vieleck1
PunktVieleck1 = PointIn(Vieleck1)
E1_1 = Name(a)
E1_2 = Name(a)
f = false
i = false
j_1 = false
k_2 = false
N4 = 10
Q4 = 38
N5 = 9
Q5 = 34
N6 = 8
Q6 = 30
N7 = 7
Q7 = 26
N8 = 6
Q8 = 22
N9 = 5
Q9 = 18
N10 = 4
Q10 = 14
N11 = 3
Q11 = 10
N12 = 2
Q12 = 6
N13 = 1
Q13 = 2
Y1_1 = Name(a)
S1_1 = Name(a)
T1_1 = Name(Vieleck1)
U1_1 = Name(S1)
S4 = 9
T4 = 34
S5 = 10
T5 = 38
S6 = 9
T6 = 34
S7 = 8
T7 = 30
S8 = 7
T8 = 26
S9 = 6
T9 = 22
S10 = 7
T10 = 26
S11 = 8
T11 = 30
S12 = 9
T12 = 34
S13 = 10
T13 = 38
k = false
N19: a
O4: (N4 * 4) - 2
O5: (N5 * 4) - 2
O6: (N6 * 4) - 2
O7: (N7 * 4) - 2
O8: (N8 * 4) - 2
O9: (N9 * 4) - 2
O10: (N10 * 4) - 2
O11: (N11 * 4) - 2
O12: (N12 * 4) - 2
O13: (N13 * 4) - 2
P4: (N4 * 2) + ((N4 - 1) * 2)
P5: (N5 * 2) + ((N5 - 1) * 2)
P6: (N6 * 2) + ((N6 - 1) * 2)
P7: (N7 * 2) + ((N7 - 1) * 2)
P8: (N8 * 2) + ((N8 - 1) * 2)
P9: (N9 * 2) + ((N9 - 1) * 2)
P10: (N10 * 2) + ((N10 - 1) * 2)
P11: (N11 * 2) + ((N11 - 1) * 2)
P12: (N12 * 2) + ((N12 - 1) * 2)
P13: (N13 * 2) + ((N13 - 1) * 2)
N14 = NaN
N15 = NaN
O19: (N19 * 4) - 2
P19: (N19 * 2) + ((N19 - 1) * 2)
O22: Vieleck1