Skizze_Schnellster Weg
Author: Mareike Hofmeier

Veranschaulichung der Aufgabensituation

Acker

L =  \sqrt{ 400^2 + d^2 } +1000 - d 

[BC] = 1000m

Straße

C = Point(xAxis)
B = (0, 0)
A = (-1000, 400)
c = Segment(A, C)
b_1 = Segment(C, B)
D = Point(b_1)
a = Segment(A, D)
b = Segment(D, B)
d = Segment(C, D)
f(x) = 2 sqrt(160000 + x^(2)) + 1000 - x
F: (d, 2 sqrt(160000 + d^(2)) + 1000 - d - 1500)
text4: "F=" + (f(d))
e = OrthogonalLine(F, xAxis)
G = Intersect(e, xAxis)
g = Segment(F, G)
h = Segment(B, G)
text7: "d=" + d